The cross product, also known as the vector product, is an operation between two vectors that results in a third vector orthogonal to both of the original vectors. It is denoted by the symbol $\times$. Given two vectors $\mathbf{A}$ and $\mathbf{B}$, their cross product $\mathbf{C}$ can be calculated as:
\begin{equation}
\mathbf{C} = \mathbf{A} \times \mathbf{B}
\end{equation}
The cross product can be defined using the determinant of a 3×3 matrix:
\begin{equation}
\mathbf{C} = \begin{vmatrix}
\mathbf{i} & \mathbf{j} & \mathbf{k} \\
A_x & A_y & A_z \\
B_x & B_y & B_z
\end{vmatrix}
\end{equation}
where $\mathbf{i}$, $\mathbf{j}$, and $\mathbf{k}$ are the unit vectors in the $x$, $y$, and $z$ directions, respectively. The components of the resulting vector $\mathbf{C}$ are given by:
\begin{align}
C_x &= A_yB_z – A_zB_y \\
C_y &= A_zB_x – A_xB_z \\
C_z &= A_xB_y – A_yB_x
\end{align}
Example
Let’s consider the vectors $\mathbf{A} = 3\mathbf{i} + 2\mathbf{j} – \mathbf{k}$ and $\mathbf{B} = 2\mathbf{i} + 4\mathbf{j} + \mathbf{k}$. We can calculate their cross product as follows:
\begin{align*}
C_x &= (2)(-1) – (4)(-1) = -2 + 4 = 2 \\
C_y &= (1)(3) – (2)(-1) = 3 + 2 = 5 \\
C_z &= (3)(4) – (2)(2) = 12 – 4 = 8
\end{align*}
Therefore, the cross product of $\mathbf{A}$ and $\mathbf{B}$ is $\mathbf{C} = 2\mathbf{i} + 5\mathbf{j} + 8\mathbf{k}$.
Properties
The cross product has several important properties:
- The cross product of two vectors is orthogonal to both of the original vectors.
- The magnitude of the cross product is equal to the area of the parallelogram formed by the original vectors.
- The direction of the cross product follows the right-hand rule: if you curl the fingers of your right hand from the direction of $\mathbf{A}$ to $\mathbf{B}$, then your thumb points in the direction of $\mathbf{C}$.
- The cross product is anti-commutative, meaning that $\mathbf{A} \times \mathbf{B} = -(\mathbf{B} \times \mathbf{A})$.
- If the cross product of two vectors is zero, then the vectors are parallel or anti-parallel.
